Order in Initialization

Do you know what the following piece of code will print?

	class MyClass {
	MyClass() {
	System.out.println("MyClass");
	}
	MyClass(String id) {
	System.out.println("MyClass " + id);
	}
	}
	class Parent {
	// static String id = "Parent";
	// MyClass instance1 = new MyClass(id);
	MyClass instance1 = new MyClass();
	Parent() {
	System.out.println("Parent");
	}
	}
	public class Test extends Parent {
	// static String id = "Test";
	// MyClass instance2 = new MyClass(id);
	MyClass instance2 = new MyClass();
	Test(String name) {
	System.out.println("Test");
	}
	public static void main(String[] args) {
	new Test("Cristina");
	}
	}

view raw TestInitialization(OrderOfConstructorCalls).java hosted with ❤ by GitHub

The answer is:

MyClass
Parent
MyClass
Test

Now can you tell which instance (instance1 or instance2) prints the first "MyClass" string?
 
Uncomment the commented lines and see for yourself!

http://stackoverflow.com/questions/14805547/are-fields-initialized-before-constructor-code-is-run-in-java

http://stackoverflow.com/questions/17806342/order-of-constructor-calls-in-multilevel-inheritance-in-java